is the slope of a line that lies tangent to the curve at a specific point. It can also be defined as the instantaneous rate of change of function as it approaches to zero by applying the limit. <\/span><\/p>\nThe derivative can find the differential of the exponential function, polynomial function, constant function, linear function, logarithmic function, or the trigonometric function. <\/span><\/p>\nThe derivative has various types to solve complex calculus problems. The types of differentiation are:<\/span><\/p>\n\n- The explicit derivative<\/span><\/li>\n
- The implicit derivative<\/span><\/li>\n
- The partial derivative<\/span><\/li>\n
- The directional derivative <\/span><\/li>\n<\/ul>\n
All the above types of derivatives have different techniques to find the derivative of various kinds of functions and equations. The explicit derivative is the main type of derivative that is used to find the derivative of a one-variable function. <\/span><\/p>\nThe equation and multivariable functions are not involved in this type of differentiation. It is denoted by d\/dx or f\u2019(x). Implicit differentiation is the second type of derivative that is used to find the derivative of the implicit function or equation.<\/span><\/p>\nIn this type of derivative, differential notation is applied on both sides of the equation. It differentiates the function of y in terms of x without taking it as a constant. It is denoted by dy\/dx or y\u2019(x).<\/span><\/p>\nThe third type of derivative is the partial derivative that deals with the multivariable function. the function f(x, y, z) can be differentiated with respect to x, y, or z. It is denoted by \u2202f(x, y, z) \/ \u2202x, \u2202f(x, y, z) \/ \u2202y, or \u2202f(x, y, z) \/ \u2202z.<\/span><\/p>\nThe directional derivative is also a type of derivative that is used to find the direction of the function by taking the dot product of the gradient and the normalized vector. It is denoted by \u2202<\/span>u<\/span> f(x, y, z).<\/span><\/p>\nRules of differentiation<\/b><\/h2>\n
There are various rules of differentiation used to solve the problems of the derivative. These rules are:<\/span><\/p>\n\n- The sum rule<\/b><\/li>\n<\/ul>\n
d\/dx [h(x) + g(x)] = d\/dx [h(x)] + d\/dx [g(x)]<\/span><\/p>\n\n- The constant rule<\/b><\/li>\n<\/ul>\n
d\/dx [C] = 0<\/span><\/p>\n\n- The difference rule<\/b><\/li>\n<\/ul>\n
d\/dx [h(x) – g(x)] = d\/dx [h(x)] – d\/dx [g(x)]<\/span><\/p>\n\n- The power rule<\/b><\/li>\n<\/ul>\n
d\/dx [h<\/span>n<\/span>(x)] = nh<\/span>n-1<\/span>(x) * d h(x)\/dx<\/span><\/p>\n\n- The product rule<\/b><\/li>\n<\/ul>\n
d\/dx [h(x) * g(x)] = g(x) d\/dx [h(x)] + f(x) d\/dx [g(x)]<\/span><\/p>\n\n- The quotient rule<\/b><\/li>\n<\/ul>\n
d\/dx [h(x) + g(x)] = 1\/[g(x)]<\/span>2<\/span> [g(x) d\/dx [h(x)] – f(x) d\/dx [g(x)]]<\/span><\/p>\n\n- The constant function rule<\/b><\/li>\n<\/ul>\n
d\/dx [C h(x)] = C * d\/dx [h(x)]<\/span><\/p>\nHow to find the derivative of functions?<\/b><\/h2>\n
By using the rules of differentiation, you can easily solve any problem of derivative. Below are a few examples of derivatives.<\/span><\/p>\nExample 1: For Explicit differentiation.<\/b><\/p>\n
Find the derivative of 2z<\/span>2<\/span> + 13z \u2013 4z<\/span>3<\/span> + cos(z) + 2, with respect to z?<\/span><\/p>\nSolution <\/b><\/p>\n
Step 1:<\/b> First of all, write the given function.<\/span><\/p>\nf(z) = 2z<\/span>2<\/span> + 13z \u2013 4z<\/span>3<\/span> + cos(z) + 2<\/span><\/p>\nStep 2:<\/b> Apply the notation of derivative (d\/dz) to the given function. <\/span><\/p>\nd\/dz [f(z)] = d\/dz [2z<\/span>2<\/span> + 13z \u2013 4z<\/span>3<\/span> + cos(z) + 2]<\/span><\/p>\nStep 3:<\/b> Now apply the notation of derivative separately to each function by using the sum and difference rules of differentiation.<\/span><\/p>\nd\/dz [2z<\/span>2<\/span> + 13z \u2013 4z<\/span>3<\/span> + cos(z) + 2] = d\/dz [2z<\/span>2<\/span>] + d\/dz [13z] \u2013 d\/dz [4z<\/span>3<\/span>] + d\/dz [cos(z)] + d\/dz [2]<\/span><\/p>\nStep 4:<\/b> Now differentiate the above expression by using the power, constant, trigonometry, and the constant function rule of differentiation. <\/span><\/p>\nd\/dz [2z<\/span>2<\/span> + 13z \u2013 4z<\/span>3<\/span> + cos(z) + 2] = 2d\/dz [z<\/span>2<\/span>] + 13d\/dz [z] \u2013 4d\/dz [z<\/span>3<\/span>] + d\/dz [cos(z)] + d\/dz [2]<\/span><\/p>\nd\/dz [2z<\/span>2<\/span> + 13z \u2013 4z<\/span>3<\/span> + cos(z) + 2] = 2 [2z<\/span>2-1<\/span>] + 13[z<\/span>1-1<\/span>] \u2013 4 [3z<\/span>3-1<\/span>] + [-sin(z)] + [0]<\/span><\/p>\nd\/dz [2z<\/span>2<\/span> + 13z \u2013 4z<\/span>3<\/span> + cos(z) + 2] = 2 [2z<\/span>1<\/span>] + 13[z<\/span>0<\/span>] \u2013 4 [3z<\/span>2<\/span>] + [-sin(z)] + [0]<\/span><\/p>\nd\/dz [2z<\/span>2<\/span> + 13z \u2013 4z<\/span>3<\/span> + cos(z) + 2] = 2 [2z] + 13[1] \u2013 4 [3z<\/span>2<\/span>] + [-sin(z)] + [0]<\/span><\/p>\nd\/dz [2z<\/span>2<\/span> + 13z \u2013 4z<\/span>3<\/span> + cos(z) + 2] = 4z + 13 \u2013 12z<\/span>2<\/span> – sin(z) + 0<\/span><\/p>\nd\/dz [2z<\/span>2<\/span> + 13z \u2013 4z<\/span>3<\/span> + cos(z) + 2] = 4z + 13 \u2013 12z<\/span>2<\/span> – sin(z) <\/span><\/p>\nYou can use a <\/span>derivative calculator<\/span><\/a> to find the derivative of any function in a fraction of seconds with steps. Follow the below steps to differentiate the functions by using this tool.<\/span><\/p>\nStep 1:<\/b> Input the function.<\/span><\/p>\nStep 2:<\/b> Select the independent variable.<\/span><\/p>\nStep 3:<\/b> Write the order of derivatives.<\/span><\/p>\nStep 4<\/b>: Click the calculate button.<\/span><\/p>\nStep 5:<\/b> The result with steps will show below the calculate button.<\/span><\/p>\nExample 2: For implicit differentiation<\/b><\/p>\n
Fid the derivative of 12xy<\/span>2<\/span> + 2y<\/span>3<\/span> \u2013 4y<\/span>4<\/span> = (4x<\/span>5<\/span> * 2x<\/span>3<\/span>) + 7x + 3y, with respect to x?<\/span><\/p>\nSolution<\/b><\/p>\n
Step 1:<\/b> First of all, write the given function.<\/span><\/p>\n12xy<\/span>2<\/span> + 2y<\/span>3<\/span> \u2013 4y<\/span>4<\/span> = (4x<\/span>5<\/span> * 2x<\/span>3<\/span>) + 7x + 3y<\/span> <\/b><\/p>\nStep 2:<\/b> Apply the notation of derivative (d\/dx) on the both sides of the given function. <\/span><\/p>\nd\/dx [12xy<\/span>2<\/span> + 2y<\/span>3<\/span> \u2013 4y<\/span>4<\/span>] = d\/dx [(4x<\/span>5<\/span> * 2x<\/span>3<\/span>) + 7x + 3y]<\/span><\/p>\nStep 3:<\/b> Now apply the notation of derivative separately to each function by using the sum, product, and difference rules of differentiation.<\/span><\/p>\nd\/dx [12xy<\/span>2<\/span>] + d\/dx [2y<\/span>3<\/span>] \u2013 d\/dx [4y<\/span>4<\/span>] = d\/dx [(4x<\/span>5<\/span> * 2x<\/span>3<\/span>)] + d\/dx [7x] + d\/dx [3y]<\/span><\/p>\ny<\/span>2<\/span>d\/dx [12x] + 12xd\/dx[y<\/span>2<\/span>] + d\/dx [2y<\/span>